Question

On a coordinate plane, 3 parallelograms are shown. Parallelogram A B C D has points (3, 5), (6, 5), (4, 1), (1, 1). Parallelogram A prime B prime C prime D prime has points (3, negative 5), (6, negative 5), (4, negative 1), (1, negative 1). Parallelogram A double-prime B double-prime C double-prime D double-prime has points (negative 3, negative 4), (0, negative 4), (negative 2, 0), (negative 4, 0). Which rule describes the composition of transformations that maps pre-image ABCD to final image A"B"C"D"? Reflection across the x-axis composition translation of negative 6 units x, 1 unit y. Translation of negative 6 units x, 1 unit y composition reflection across the x-axis. 90 degree rotation about point 0 composition translation of negative 6 units x, 1 unit y. Translation of negative 6 units x, 1 unit y composition 90 degree rotation about point 0.

Answer 1

Translation of negative 6 units x, 1 unit y composition reflection across the x-axis.

Explanation:

The answer above is correct.

Answer 2

The correct answer is Translation of negative 6 units x, 1 unit y composition reflection across the x-axis.

Here's the step-by-step breakdown:

Parallelogram A B C D to A' B' C' D':

Reflection across the x-axis: This flips the parallelogram across the x-axis, resulting in A' B' C' D'.

Parallelogram A' B' C' D' to A" B" C" D":

Translation of negative 6 units x, 1 unit y: This shifts the parallelogram 6 units to the left and 1 unit upwards, resulting in A" B" C" D".

Therefore, the overall composition of transformations is Translation of negative 6 units x, 1 unit y composition reflection across the x-axis.