Answer: 42.14
![cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/61e8u9cfza9ghk51td2ae543e9polghsyy.png)
Explanation:
Assuming that the width of the rectangle is 7 cm, the semi-circle's radius is also 7 cm.
Let's calculate the area of the two semi-circles, which in total makes a whole circle.
The formula for a circle is
![a=2\pi r^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/n0byv8rcuo7zqzi5845014a6zcya4112hf.png)
Since r = 7, plug it in the formula:
![a=2\pi (7)^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/1x3ksh7bm6uab44so5pz9c3xelfolycf6r.png)
![a=49\pi =153.86 cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/21ghst404jdcqf7hay62a5zb5wjpd1t5ru.png)
Now, to figure out the length of the rectangle, look at the semi-circles. Their radius is 7 cm, so their diameter is 14 cm. We have two semi-circles with the diameter (14 cm), so we can say that the width is 28 cm.
Area of a rectangle:
![a=lw](https://img.qammunity.org/2021/formulas/mathematics/high-school/v6zpq1gl9wgpnirpztx0ge1lxvmfg3oncd.png)
![a=7*28=196cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/hji1414cjsemp7ncnjgi1gfi4asy2912gq.png)
To find the area of the shaded region, we subtract the area of the semi-circles to the rectangle, which should be:
![196 - 153.86=42.14 cm^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/2ka2ks5d3leh6ci6090s8dmrrgli59dqxx.png)