Question

Qual o valor que Z assume?
-Cz+ 6z = Tz+ 83

Answer 1

`\large \boxed{z = (83)/(6 - C - T)}`

Explanation:

`\begin{array}{rccl}-Cz + 6z & = & Tz + 83 & \\6z -Cz - Tz &= & 83 & \text{Subtracted Tz from each side}\\z(6 - C - T) & = & 83 & \text{Removed the common factor}\\z& = & \mathbf{(83)/(6 - C - T)} &\text{Divided each side by 6 - C - T}\\\end{array}\\\\\large \boxed{\mathbf{z = (83)/(6 - C - T)}}`