Question

PLEASE HELP ASAP 30 POINTS MY BRAINS TO FRIED TO THINK. I ALREADY DID A PART OF THE ANSWER, PLEASE SOLVE THE REST.

An expression is shown below:

f(x) = −16x2 + 22x + 3

What are the coordinates of the vertex? Justify your answers and show your work.

ANSWER:
To find the vertex: the x value = f(x)=ax^2+bx+c= is -b/(2a), and y value = f(-b/(2a)).
Given: f(x)= −16x2 + 22x + 3
a= -16 and b= 22
b-/2a= -(22)/(-16*2)=11/16
PLEASE SOLVE THE REST

Answer 1

Vertex: (11/16,169/16)

Explanation:

You plug in the x value to find the y value so

-16(11/16)^2+22(11/16)+3=

-16(121/256)+121/8+3=

-121/16+145/8=

Y=169/16

Answer 2

Vertex is at (11/16, 169/16)

Explanation:

f(x) = −16x^2 + 22x + 3

The vertex is at x = -b/2a

x = -22/(2)(-16) = -22/-32 = 11/16

f(11/16) = -16 (11/16)^2 +22(11/16) +3

=-16 *11/16 *11/16 +22*11/16 +3

= -121/16 +242/16 +3

-121/16 +242/16 +48/16

169/16

Vertex is at (11/16, 169/16)