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F = freckles f= no freckles

3. A man who is heterozygous for freckles marries a woman who is also heterozygous for freckles.
a. What are the two genotypes? _________________
b. % of offspring that will be homozygous dominant ___________
c. % of offspring that will be heterozygous ___________
d. % of offspring that will be homozygous recessive ___________
e. % of offspring that will have freckles ___________
f. % of offspring that will not have freckles__________

User XpertSiji
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2 Answers

3 votes

A. Ff for both

B. 75%

C. 25%

D.0%

E.75%

F. 25%

Hope this helps you:)

User Stefos
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1 vote

Answer:

a. Ff for both

b. 25%

c. 50%

d. 25%

e. 75%

f. 25%

since both are heterozygous, when you genetically cross them, the probability of getting homozygous dominant is 1/4(25%), heterozygous will be 50%, homozygous recessive is 25%, 75% will have freckles since F is the dominant for freckles. 25% will have no freckles.

F = freckles f= no freckles 3. A man who is heterozygous for freckles marries a woman-example-1
User Zhen
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4.5k points