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The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the admission fee collected totaled $862. How many children and how many adults were admitted?

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Answer:

188 children and 145 adults were admitted in the park.

Explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be
x.

And the the number of adults admitted be
y.

So, the total people enter the park:


x+y=333\\\\x=333-y\ \ \ ...(1)

Thus, the total amount collected of the admission fee:


1.50(x)+4(y)=862\\\\

Substituting the value of
x from equation (1):


1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of
y in equation (1) we get:


x=333-y\\\\x=333-145\\\\x=188.

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

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