Question

X^2+y^2-10x-16y+53=0
What is the center of the circle?
What is the radius of the circle?

Answer 1

Explanation:

hello : Completing The Square

X²+y²-10x-16y+53=0 means : (x²-10x+25-25)+(y²-16y+16-16)+53 =0

(x²-10x+25)-25)+(y²-16y+64)-64+53 =0

(x+5)²+(y-8)² -25-64+53=0

(x+5)²+(y-4)² = 6² standard form

the center is (-5 , 4) and the radius : 6