Answer:
Explanation:
Let
After one year, in 2001, the price is $a_2$, where
$a_2= a_1-a_1\times (0.15)$
$\therefore a_2=a_1(1-0.15)=a_0(0.85)$
Now after two years, in 2002, let the price be $a_3$
The pattern is pretty clear. After $n$ years, in $200n$ the price will be:
$a_n= a_0(0.85)^{n-1}$