Question

A sports shop sells 3 light bowling balls and 3 heavy bowling balls for ten-pin bowling. The weight of a heavy bowling ball is twice that of a light bowling ball. The total weight of the 6 bowling balls is 52.65 pounds. Find the total weight of the 3 heavy bowling balls to the nearest pound.

Answer 1

The weigth of the three heavy balls is 35.1 pounds.

Explanation:

In order to solve this problem we will call the weigth of the light ball by "l" and the weigth of the heavy ball by "h". The total weigth of the six balls is 52.65 pounds, so we have:

3*l + 3*h = 52.65

We know that the weigth of the heavy ball is twice the weight of the light ball, so we have:

h = 2*l

We can use this value on the equation to solve for "l". We have:

3*l + 3*(2*l) = 52.65

3*l + 6*l = 52.65

9*l = 52.65

l = 52.65/9 = 5.85 pounds

h = 2*l = 2*5.85 = 11.7 pounds

3*h = 35.1 pounds

The weigth of the three heavy balls is 35.1 pounds.