Answer:
8i - 7j - 9k
Explanation:
We have three points:
A (1,0,3)
B (2,5,0)
C (3,1,4)
First of all, we write the following two vectors:
![AB=(2-1,5-0,0-3)=(1,5,-3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/t66p7vt8h6uo2xslfmqweq93nggcgqt227.png)
![BC=(3-2,1-5,4-0)=(1,-4,4)](https://img.qammunity.org/2021/formulas/mathematics/high-school/x4d1u1oajfr11l5zcgbw6gx9hqjney21oi.png)
These two vectors connect A with B and B with C, and since these 3 points lie on the plane, the two vectors also lie on the plane.
Therefore, the cross product of these two vectors must be a vector perpendicular to the plane.
The cross product of the two vectors is:
![AB * BC = i(5\cdot 4 -(-3\cdot-4))+j(-3\cdot 1 -1\cdot 4)+k(1\cdot -4-5\cdot 1)=\\=8i-7j-9k](https://img.qammunity.org/2021/formulas/mathematics/high-school/h4ppb2kxiqau5qf28bd72dilbcl6iv4jp6.png)
And the equation of the plane can be found as:
![8(x-a_x)-7(y-a_y)-9(z-a_z)=0\\8(x-1)-7(y-0)-9(z-3)=0\\8x-7y-9z=-19](https://img.qammunity.org/2021/formulas/mathematics/high-school/wiohujj59364v87hdtzsdzm2rdnmu8lijt.png)