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Evaluate Loga√44+ Log a√275- Log 11a
They all have base 10

1 Answer

4 votes

Answer:


log(10a)

Explanation:


log(a√(44))+log(a \sqrt275)-log(11a)

We can simplify this using these log laws:


log(a)+log(b)=log(ab)\\log(a)-log(b)=log((a)/(b))


log((a^2√(44) √(275))/(11a))

We also have laws to simplify square roots


√(a)*√(b) = √(ab)

So this becomes


log((a^2√(12100))/(11a))


√(12100) = 110

so this becomes


log((110a^2)/(11a))=log(10a)

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