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(Photo attached) Trig question. Thanks in advance! :)

(Photo attached) Trig question. Thanks in advance! :)-example-1
User MikeBeaton
by
6.2k points

1 Answer

3 votes

Answer:

tan(α+β) ≈ 5.8498

Explanation:

tan(α+β) = tan(arccos(0.637) +arcsin(0.498)) = tan(50.4315° +29.8677°)

= tan(80.2993°) ≈ 5.8498

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Comment on this working

You may be expected to use trig identities to find ...

tan(α) = √(1-cos²(α))/cos(α)

tan(β) = sin(β)/√(1-sin²(β))

tan(α+β) = (tan(α)+tan(β))/(1 -tan(α)tan(β))

Or

sin(α) = √(1-cos²(α))

cos(β) = √(1 -sin²(β))

tan(α+β) = sin(α+β)/cos(α+b)

= (sin(α)cos(β) +cos(α)sin(β))/(cos(α)cos(β) -sin(α)sin(β))

Either way, a calculator is definitely involved. Since a calculator is required for the solution, it is far easier to do the problem using inverse trig functions.

User Teoman Kirac
by
6.7k points
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