Question

6. The temperature of an iron block decreases from 85°C to 25°C. If the mass for

the block is 1.2 kg, calculate the heat lost by the block. (Citon = 0.115 cal/g.°C)

Answer 1

8280 cal

Explanation:

Q=mc(delta)T

Q=1200(0.115)(-60)

Q=8280 cal

I used 1200 g instead of 1.2 kg