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What are the [H+] and [OH-] for a substance with a ph of 9.2?​

1 Answer

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Answer:

The answer to your question is [H⁺] = 6.31 x 10⁻¹⁰ M [OH⁻] = 1.58 x 10⁻⁵ M

Step-by-step explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 9.2

Process

To find the answer to this question we must start by using the formula of pH and simplify to find the [H⁺] then calculate the pOH to find the [OH⁻]

1.- Write the formula of pH

pH = -log [H⁺]

2.- Find the [H⁺]

9.2 = -log[H⁺]

-Solve for [H⁺]

[H⁺] = antilog (-9.2)

-Result

[H⁺] = 6.31 x 10⁻¹⁰ M

3.- Calculate the pOH

pH + pOH = 14

-Solve for pOH

pOH = 14 - 9.2

-Result

pOH = 4.8

4.- Calculate the [OH⁻]

-Substitution

4.8 = -log [OH⁻]

-Solve for [OH⁻]

[OH⁻] = antilog (-4.8)

-result

[OH⁻] = 1.58 x 10⁻⁵ M

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