Question

Using the combined gas law, if the volume of a gas at 155kPa changes from 22L to 10L. What is the new pressure if the temperature remains constant?

Answer 1

The answer to your question is P2 = 342 kPa

Step-by-step explanation:

Data

Pressure 1 = P1 = 155 kPa

Volume 1 = V1 = 22 l

Pressure 2 = P2 = ?

Volume 2 = V2 = 10 l

Temperature = constant

Process

1.- Write the equation of the combined gas law

P1V1/T1 = P2V2/ T2

Cancel T1 and T2 because they measure the same

P1V1 = P2V2

-Solve for P2

P2 = P1V1/V2

2.- Substitution

P2 = (155 x 22) / 10

3.- Simplification

P2 = 3410 / 10

4.- Result

P2 = 342 kPa