Question

How do you solve the system of equations 3x + 8y=15 and 2x + 8y

Answer 1

like this watch.

Explanation:

Using the first equation, solve for x:

`3x+8y=15\\`

Subtract 8y from both sides

`3x+8y-8y=15-8y\\3x=15-8y`

Divide both sides by 3

`(3x)/(3)=(15-8y)/(3) \\\\x=5-(8y)/(3)`

Keep that in mind...Now solve for y

`3x+8y=15`

Subtract 3x from both sides

`3x-3x+8y=15-3x\\8y=15-3x`

Divide both sides by 8

`(8y)/(8)=(15-3x)/(8) \\\\y=(15-3x)/(8)`

Now, plug these into 2x+8y

`2(5-(8y)/(3))+8((15-2x)/(8))`

Simplify

`10-(16y)/(3) +15-2x\\\\-2x-(16y)/(3) +25`

omg nevermind

it goes on forever

You don't solve this

Unless....

You messed up on 2x+8y and forgot the equal sign, which would make it an equation...I got played.