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11. Which of the following gives the correct relation between the acceleration due to gravity and period of a pendulum?

g = 2πLT2
g = 4π2LT2
g = 2πLT
g = 2π2LT

Please show all of your algebra.

1 Answer

2 votes


\\ \rm\rightarrowtail T=2\pi\sqrt{(l)/(g)}

  • Derive g


\\ \rm\rightarrowtail T^2=4\pi^2(l)/(g)


\\ \rm\rightarrowtail g=(4\pi ^2\ell)/(T^2)


\\ \rm\rightarrowtail g=\left((2\pi√(l))/(T)\right)^2

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