Question

A direct current of 3.0 A flows through a circuit consisting of a battery and a 6.0 A resistor. Calculate the potential difference across the resistor. a​

Answer 1

Question :-

• A Direct Current of 3.0 A flows through a Circuit consisting of a Battery and a 6.0 Ohm's Resistor. Calculate the Potential Difference across the Resistor .

Answer :-

• Potential Difference is 18 Volt's .

Explanation :-

As per the provided information in the given question, we have been given that the Current of the Device is 3.0 Ampere . The Resistance is given as 6.0 Ohm's . And, we have been asked to calculate the Potential Difference .

As we know ,

• V = I R

Where ,

• V denotes to Potential Difference
• I denotes to Current
• R denotes to Resistance

Therefore , by Substituting the given values in the above Formula :-

`\sf {\dag \: \: \: Potential \: Difference \: = \: Current \: * \: Resistance}`

`\sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3.0 \: * \: 6.0}`

`\sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3 \: * \: 6}`

`\bf {\Longrightarrow \: \: \: \bf {Potential \: Difference \: = \: 18 \: }}`

Hence :-

• Potential Difference = 18 Volt's .

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Additional Information :-

`\Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: * \: Resistance}`

`\Longrightarrow \: \: \: \sf {Current \: = \: \frac {Voltage}{Resistance} }`

`\Longrightarrow \: \: \: \sf {Resistance \: = \: \frac {Voltage}{Current} }`

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