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Somebody help me with this

Somebody help me with this-example-1
User Raky
by
3.7k points

2 Answers

5 votes

Answer:

A: 112°

B: 95°

C: 68°

D: 85°

Explanation:

Opposite angles add up to 180

8z + 14z - 7 = 180

22z = 187

z = 8.5

A = 14(8.5) - 7

A = 112

C = 8(8.5)

C = 68

D = 10(8.5)

D = 85

B = 180 - 85

B = 95

User Saketh
by
4.0k points
5 votes

Given:

Given that the quadrilateral ABCD is inscribed in the circle.

The measure of ∠A is (14z - 7)°

The measure of ∠C is (8z)°

The measure of ∠D is (10z)°

We need to determine the measures of ∠A, ∠B, ∠C and ∠D

Value of z:

We know the property that the opposite angles of a quadrilateral inscribed in a circle are supplementary.

Thus, we have;


\angle A+ \angle C=180^(\circ)

Substituting the values, we have;


14z-7+8z=180


22z-7=180


22z=187


z=8.5

Thus, the value of z is 8.5

Measure of ∠A:

The measure of ∠A can be determined by substituting the value of z.

Thus, we have;


\angle A=14(8.5)-7


\angle A=119-7


\angle A=112^(\circ)

Thus, the measure of ∠A is 112°

Measure of ∠C:

The measure of ∠C can be determined by substituting the value of z.

Thus, we have;


\angle C=8(8.5)


\angle C =68^(\circ)

Thus, the measure of ∠C is 68°

Measure of ∠D:

The measure of ∠D can be determined by substituting the value of z.

Thus, we have;


\angle D=10(8.5)


\angle D=85^(\circ)

Thus, the measure of ∠D is 85°

Measure of ∠B:

The angles B and D are supplementary.

Thus, we have;


\angle B+ \angle D=180^(\circ)

Substituting the values, we get;


\angle B+ 85^(\circ)=180^(\circ)


\angle B=95^(\circ)

Thus, the measure of ∠B is 95°

User Stanley Ko
by
3.9k points