Answer:
The total heat required is 35807 J
Step-by-step explanation:
Step 1: Data given
Mass of water = 15.0 grams
Initial temperature of water = 87.0 °C
Temperature of steam = 135.0 °C
ΔHfus = 334 J/g
ΔHVap = 2260 J/g
Step 2: Calculate heat required to heat water from 85 to 100 °C
Q = m*c*ΔT
⇒Q = the heat required = TO BE DETERMINED
⇒m = the mass of water = 15.0 grams
⇒c= the specific heat of water = 4.18 J/g°C
⇒ΔT = the change of temperature = T2 - T1 = 100 - 87 = 13°C
Q = 15.0 * 4.18 J/g°C * 13 °C
Q = 815.1 J
Step 3: Calculate heat required to change water at 100 °C to steam
Q = m * ΔHVap
Q = 15.0 grams * 2260 J/g
Q = 33900 J
Step 4: Calculate heat required to heat steam from 100 °C to 135 °C
Q = m*c*ΔT
⇒Q = the heat required = TO BE DETERMINED
⇒m = the mass of water = 15.0 grams
⇒c= the specific heat of steam = 2.09 J/g°C
⇒ΔT = the change of temperature = T2 - T1 = 135 - 100 = 35°C
Q = 15.0 * 2.09 * 35 °C
Q = 1097.25 J
Step 5: Calculate the total heat required
Q = 35807 J
The total heat required is 35807 J
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