How many grams of potassium nitrate are required to prepare 0.250 L of a 0.700 M solution? 2.8 g 101.0 g 0.175 g 17.7 g

asked Feb 18, 2021 213k views

2 votes

How many grams of potassium nitrate are required to prepare 0.250 L of a

0.700 M solution?
2.8 g

101.0 g

0.175 g

17.7 g

7.4k points

Please log in or register to add a comment.

5 votes

Answer:

Think its 17.7 g.

Step-by-step explanation:

Pradeepcep answered Feb 22, 2021

7.8k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.2m questions

11.9m answers