How many grams of potassium nitrate are required to prepare 0.250 L of a 0.700 M solution? 2.8 g 101.0 g 0.175 g 17.7 g

asked Feb 18, 2021 213k views

2 votes

How many grams of potassium nitrate are required to prepare 0.250 L of a

0.700 M solution?
2.8 g

101.0 g

0.175 g

17.7 g

6.7k points

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5 votes

Answer:

Think its 17.7 g.

Step-by-step explanation:

Pradeepcep answered Feb 22, 2021

7.3k points

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