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Sketch given function
y=-x^2(x+6)

User Undine
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1 Answer

3 votes

Answer:

see attached

Explanation:

The leading coefficient of this cubic (odd-degree) function is negative, so the overall shape of the curve will be downward-sloping (\). The zeros of the factors are at x=-6 and x=0 (multiplicity 2), so we know the first crossing of the x-axis will occur at x=-6. The graph will touch, but not cross, the x-axis at x=0 and continue descending from there.

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The local minimum will be located 2/3 of the way from the "touch" point to the other x-intercept, so is at x=-4. The value of the function there is ...

y = -(-4)²(-4+6) = -32

The graph is symmetrical about the inflection point halfway between the local extremes, which point is (-2, -16). Then another point on the curve will be 6 units to the right of the local minimum, at (2, -32).

Sketch given function y=-x^2(x+6)-example-1
User Jozh
by
7.0k points