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Write an equation of the circle with center (5, 2) and diameter 12.

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Answer:


(x-5)^2 + (x-2)^2 = 6^(2)

Explanation:

Standard equation of a circle is


(x-x_(0))^2-(y-y_(0))^2 = r^2\\r=(1)/(2)d

As the radius is half of the diameter we can divide 12 by 2 to get a radius, then we can input values into this equation.

User GrandMagus
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