Answer:
![\bigtriangleup A\approx 82.41\ cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/w0ln698pgmkuq9ff2cq7m7i35hiawtt52x.png)
Explanation:
-Assume the cans are arranged in a two by three dimensions.
-Therefore the length of the box is equivalent to 3 diameters and the width is equivalent to two diameters:
![D=2r=2* 4=8\ cm\\\\Length=3D=3* 8=24\\\\Width=2D=2* 8=16](https://img.qammunity.org/2021/formulas/mathematics/college/8ex0xjtdn936no3vvhyiathsgqt2a78q5b.png)
![cm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/q63alhyp4ler14tm4wtg90o3x5fo3g70wr.png)
#The area of the cardboard box is calculated as:
![Area=lw\\\\=24* 16\\\\=384\ cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/7gbzfd54oou2dpikrvuu8cu9kdhlbsk82k.png)
#The total bottom areas of the 6 cans is:
![A_6=6\pi r^2\\\\=6\pi * 4^2\\\\=301.593\ cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/foxxnskec6r9lg2u4dwnom9n4k7tikkp1n.png)
#The area not covered is the difference between the area of the box and the total bottom areas of the 6 cans:
![\bigtriangleup A=A_b-A_c\\\\=384-301.593\\\\=82.407\ cm^2\\\\\approx 82.41\ cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/n6qjx1pym6fo47p1olc0ejlme3usgs0n17.png)
Hence, the area not covered is approximately
![82.41\ cm^2](https://img.qammunity.org/2021/formulas/mathematics/college/ybl4t7p8tpc2igyha1ap09f06y0s7vv2ad.png)
*Note that whichever order of arrangement the cans assume, the areas of the boxes will be the same.