Question 1

Solve for x ~

$x {}^(2) - 5x + 6 = 0$

thankyou ~

Question 2

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.
x= 3, 2

Question 3

$\boxed{\bold{x = 2, 3}}$

Stepwise Solving:

$\rightarrow \sf x^2-5x + 6 = 0$

$\sf use \ the \ formula : x = ( -b \pm √(b^2 - 4ac))/(2a) \ \ when \ ax^2 + bx + c = 0$

Identify the coefficients:

Solve for x:

$\dashrightarrow \ \sf x=(-\left(-5\right)\pm √(\left(-5\right)^2-4 \ x \ 1 \ x \ 6))/(2 \ x \ 1)$

$\dashrightarrow \ \sf x=(\left5\right\pm √(\left25-24))/(2)$

$\dashrightarrow \ \sf x=(\left5\right\pm √(1))/(2)$

$\dashrightarrow \ \sf x=(\left5\right\pm1)/(2)$

$\dashrightarrow \ \sf x=(\left5\right+ 1)/(2) \ , (\left5\right- 1)/(2)$

$\dashrightarrow \ \sf x=(6)/(2) \ , \ (4)/(2)$

$\dashrightarrow \ \sf x= 3, \ 2$

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