Answer:
a1= 3
a2 = 4a(2-1)+2
= 4a1 +2
= 4( 3)+ 2 = 14
a3= 4a(3-1) +2
= 4a2 +2
= 4(14)+2
= 56+2 = 58
a4= 4a(4-1)+2
= 4a3 +2
= 4( 58) + 2
= 232+2= 234
234
Explanation:
Using the recursive formula and a₁ = 3, then
a₂ = 4a₁ + 2 = 4(3) + 2 = 12 + 2 = 14
a₃ = 4a₂ + 2 = 4(14) + 2 = 56 + 2 = 58
a₄ = 4a₃ + 2 = 4(58) + 2 = 232 + 2 = 234
Thus the 4 th term is 234
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