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What is the range of the function y = 2x2 + x - 1 when the domain is {-2, -1, 0, 1}?

User SimaPro
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1 Answer

2 votes

If we transform each of the points we have


f(-2)=2(-2)^2+(-2)-1 = 8-2-1=5


f(-1)=2(-1)^2+(-1)-1 = 2-1-1=0


f(0)=2(0)+0-1=0+0-1=-1


f(1)=2(1)^2+(1)-1 = 2+1-1=2

The range is simply the set of all possible outputs.

User JCallico
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