Solve 2x^2-3x-5 using the quadratic formula

asked Sep 23, 2021 72.5k views

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2 votes

Answer:

$2 {x}^(2) - 3x - 5 \\ 2 {x}^(2) - 5x + 2x - 5 \\ 2 {x}^(2) + 2x - 5x - 5 \\ 2x(x + 1) - 5(x + 1) \\ = (2x - 5)(x + 1)$

$2x - 5 = 0 \\ 2x = 0 + 5 \\ (2x)/(2) = (5)/(2) \\ x = (5)/(2)$

$x + 1 = 0 \\ x = - 1$

hope this helps you.....!

Ephrion answered Sep 28, 2021

4.3k points

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