How do you reduce ln(3^-e e^3) to simplest form

Question

asked Jun 26, 2021 174k views

1 Answer

Leoluyi · Answer 1 · 2021-07-01T12:17:57+0000

The logarithm of a product is equal to the sum of logarithms:

$\ln(3^(-e)e^3)=\ln3^(-e)+\ln e^3$

Drop the exponents:

$-e\ln3+3\ln e$

The logarithm of a number is equal to 1 if the base of the logarithm is the same as the number itself:

$-e\ln3+3$