Question

A 15.75 g piece of iron absorbs 1097 joules of heat energy, and its temperature changes from 25°C to 177°C. Calculate the specific heat capacity of iron

Answer 1

The answer for the following problem is mentioned below.

Step-by-step explanation:

Given:

mass of iron (m) = 15.75 grams

heat (q) = 1097 J

initial temperature (
`t_(1)`) = 25°C

final temperature (
`t_(2)`) = 177°C

To find:

specific heat (c)

We know;

c = q ÷ mΔT

where;

c represents the specific heat

q represents the heat

m represents the mass

t represents the temperature

c =
`(1097)/(15.75 * (177-25))`

c = 0.45 J/kg°C

Therefore the specific heat capacity of iron is 0.45 J/kg°C.