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What is the equation of a line that has a slope of -4/5 and point (0,-8)?

A. y = 4/5x + 8

B. y = -4/5x - 8

C. y = -4/5x + 8

D. y = 8x - 4/5

User Charitoo
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1 Answer

4 votes

Answer:

B

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = -
(4)/(5)

Note the line crosses the y- axis at (0, - 8) โ‡’ c = - 8

y = -
(4)/(5) x - 8 โ† equation of line

User Syed Abidur Rahman
by
3.5k points