Answer:
9 quarts of paint
Explanation:
-Since, the bottom area is not painted, the total area would be the sum of the two isosceles faces and the two remaining rectangles.
#Area of Isosceles faces:
![A=0.5b* \perp h, \ \perp h=11.5\ ft, \\\\2b=2*√((12.72^2-11.5^2))=10.8712\\\\2A=2* 0.5* 10.8712* 11.5\ ft\\\\=125.0188\ ft^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/egglwliz2mhwuggf27i4gw879zi2suqhpp.png)
#Area of the two rectangles:
![A_1=lw\\\\=9* 12.72\\\\=114.48\ ft^2\\\\A_2=lw, \ \ w=b=10.8712\\\\=9* 10.8712\\\\=97.8408\\\\\therefore A=A_1+A_2\\\\=114.48+97.4808\\\\=212.3208\ ft^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/ytkwgody9bjk4z3kb5ce2keb8k3l8uqxwl.png)
#The total area to be painted is the sum of all faces:
![Total \ Area=125.0188+212.3208=\\\\=337.3396\ ft^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/5vl5afx25r0q8kdbm111syje0jhar951mg.png)
Since, the area would be covered twice and that 1 quart covers 80 sq ft. Let X be the number of quarts of paint:
![Area \ Covered= 2Area\\\\=2* 337.3396\\\\=674.6792\ ft^2\\\\80 \ ft^2=1qt\\674.6792\ ft^2=X\\\\X=(674.6792)/(80)\\\\=8.43349\approx 9\ qts\ of \ paint](https://img.qammunity.org/2021/formulas/mathematics/high-school/wfim17knidiom74h5csprqtvu4033e3own.png)
Hence, you need to buy approximately 9 quarts of paint.