Question

A square current loop 5.20 cm on each side carries a 460 mA current. The loop is in a 0.900 T uniform magnetic field. The axis of the loop, perpendicular to the plane of the loop, is 30° away from the field direction.

What is the magnitude of the torque on the current loop?

Answer 1

The magnitude of the torque on the current loop is 0.0055 Nm

Step-by-step explanation:

Given data,

We have the formula,

T= u x B

Where u= i x A

T= i×A×B ×sin(30)

T=0.46×0.52² ×0.900×0.5

T=0.0055 Nm

The magnitude of the torque on the current loop is 0.0055 Nm