find the value of tan (a-b) if cos a=4/5 on the interval (270, 360) and sin b=-5/13 on the interval (270, 360)

asked Sep 22, 2021 141k views

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5 votes

We can find a and b using inverse trig functions,

$\cos(a)=(4)/(5)\implies a=\arccos\Big((4)/(5)\Big)\approx36.87 \\\sin(b)=-(5)/(13)\implies b=\arcsin\Big(-(5)/(13)\Big)\approx-22.62$

$\tan(36.87-(-22.62))\approx1.7$

Hope this helps.

Gontard answered Sep 27, 2021

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