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If the zeroes of the quadratic polynomial x 2 + (a + 1)x + b are 2 and –3, then (A) a = –7, b = –1 (B) a = 5, b = –1 (C) a = 2, b = –6 (D) a = 0, b = – 6
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If the zeroes of the quadratic polynomial x 2 + (a + 1)x + b are 2 and –3, then (A) a = –7, b = –1 (B) a = 5, b = –1 (C) a = 2, b = –6 (D) a = 0, b = – 6
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If the zeroes of the quadratic polynomial x 2 + (a + 1)x + b are 2 and –3, then
(A) a = –7, b = –1 (B) a = 5, b = –1 (C) a = 2, b = –6 (D) a = 0, b = – 6
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