Answer:
91.2°
Explanation:
There are several ways to find the a.pex angle of an isosceles triangle with all side lengths given. One of them is using the Law of Cosines:
c² = a² +b² -2ab·cos(C)
Solving for the angle C, we find ...
C = arccos((a² +b² -c²)/(2ab))
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Here, we have a=b=14 and c=20. The angle is ...
C = arccos((14² +14² -20²)/(2·14·14)) = arccos(-8/392)
C ≈ 91.16938°
The interior angle at the peak of the roof is about 91.2°.