Question

A balloon has 18.9 moles of hydrogen gas at a volume of 428 L. What would the volume of the gas be if the balloon had 14.0 moles of hydrogen gas left after 1 day?

Answer 1

V₂ = 317 L

Step-by-step explanation:

Given data:

Initial number of moles of hydrogen = 18.9 mol

Initial volume of gas = 428 L

Final volume = ?

Final number of moles = 14.0 mol

Solution:

According to the Avogadro law,

Number of moles of gas is directly proportional to the volume of gas at constant temperature and pressure.

Mathematical expression:

V₁/n₁ = V₂/n₂

V₁ = Initial Volume of balloon

n₁ = initial number of moles

V₂ = Final volume of balloon

n₂ = Final number of moles

Now we will put the values.

428 L / 18.9 mol = V₂/ 14 mol

V₂ =428 L × 14 mol / 18.9 mol

V₂ = 5992 L /18.9

V₂ = 317 L