Answer:
C+11/c+9
Explanation:
3c+33/3c+18 = c+11 / c+6
C^2+17c +66 = (c+6)(c+11)
C^2 +20c+99 = (c+11)(c+9)
So the given question becomes
{C+11/c+6} {(c+6)(c+11)/(c+11)(c+9)}
= c+11 /c+9
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