83.7k views
4 votes
How many grams of lithium carbonate are needed to make a concentration of 12.7M in a 5L solution

User DzungPV
by
2.8k points

1 Answer

4 votes

Answer:

The answer to your question is 4699 g

Step-by-step explanation:

Data

mass of Li₂CO₃ = ?

concentration = 12.7 M

volume = 5 l

Process

To solve this problem use the formula of Molarity and solve it for moles.

1.- Write the formula of Molarity

Molarity = moles / volume

-Solve it for moles

moles = Molarity x volume

2.- Substitute the values

moles = 12.7 x 5

3.- Result

moles = 63.5

4.- Calculate the molar mass of Li₂CO₃

Li₂CO₃ = (7 x 2) + (12 x 1) + (16 x 3)

= 14 + 12 + 48

= 74 g

5.- Use proportions to calculate the moles

74 g of Li₂CO₃ -------------- 1 mol

x -------------- 63.5 moles

x = (63.5 x 74 ) /

x = 4699 g

User OleGG
by
3.4k points