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An unusual lightning strike has a vertical portion with a current of –400 A downwards. The Earth’s magnetic field at that location is parallel to the ground and has a magnitude of 30 μT. In units of N (Newtons), the force exerted by the Earth’s magnetic field on the 25 m-long current is Group of answer choices 300 A, East. 0.30 A, West. 0 0.012 A, East. 0.012 A, West.

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Given that,

Current, I = 400 A (downwards)

The Earth’s magnetic field at that location is parallel to the ground and has a magnitude of 30 μT.

We need to find the force exerted by the Earth’s magnetic field on the 25 m-long current. We know that the magnetic force is given by :


F=iLB\sin\theta

Here,
\theta=90^(\circ)


F=400* 25* 30* 10^(-6)\\\\F=0.3\ N

The force is acting in a plane perpendicular to the current and the magnetic field i.e out of the plane.

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