Question

This optically active alkene was treated with HBr with and without peroxides. One of these reactions lead to the formation of two products, one of which is not optically active. The other reaction gives a single new product that is optically active. Which of the below statements best explains the observed results

Answer 1

The description of the given question is described in the explanation section below.

Step-by-step explanation:

The optically active acid chloride shown here has been tested with or without peroxides, using HBr. Almost all of these processes leads to two compounds being formed, one of which isn't optically active.

• Throughout the absence of peroxide, the attachment of HBr to either the alkene forms an incremental carbocation which keeps running the existing stereogenic nucleus, giving dual substances.
• Shaped a Meso compound chiral and sometimes a diastereomer. Well into the existence of peroxides, the binding of HBr to either the alkene brominates at the other carbon with the dual bond, producing a chiral substance and sometimes a meso component.

So, the above is the right answer.