Question

Y = x^2 - 2x; domain {-3, 0, 5}

Answer 1

The student's question involves calculating the output values of a quadratic function for a given domain. The specific output values for the domain {-3, 0, 5} of the function y = x^2 - 2x are 15, 0, and 15, respectively.

Step-by-step explanation:

The student is dealing with a question that involves the evaluation of a quadratic function y = x^2 - 2x at different values within its domain. Here, the domain is specified as the set {-3, 0, 5}. To answer the student's question, we calculate the value of y for each x in the domain:

• For x = -3: y = (-3)^2 - 2(-3) = 9 + 6 = 15
• For x = 0: y = (0)^2 - 2(0) = 0
• For x = 5: y = (5)^2 - 2(5) = 25 - 10 = 15

Therefore, the corresponding output values for the function at the points in the domain are 15, 0, and 15, respectively.

Answer 2

range:{0,15}

Step-by-step explanation:

y=x²-2x

domain:{-3,0,5}

for range

when x=-3

y=(-3)²-2×(-3)=9+6=15

when x=0

y=0-0=0

when x=5

y=5²-2×5=25-10=15

range:{0,15}

or

y=x²-2x+1-1=(x-1)²-1

when x=-3

y=(-3-1)²-1=16-1=15

when x=0

y=(0-1)²-1=1-1=0

when x=5

y=(5-1)²-1=16-1=15