Question

A loudspeaker diaphragm is producing a sound for 4.6 s by moving back and forth in simple harmonic motion. The angular frequency of the motion is 2.57 x 104 rad/s. How many times does the diaphragm move back and forth

Answer 1

Number of times the diaphragm move back and forth is 5.59×10^4

Step-by-step explanation:

Given data,

ω=4.6 s

we have the formula

f=ω/2π

The number of times the diaphragm moves back and forth in 4.6 s is

Number of times= ft

Number of times= ft

=(ω/2π) t

=(7.54×10^4 rad/sec)(4.6 s)/2π

Number of time=5.59×10^4

Number of times the diaphragm move back and forth is 5.59×10^4