Question

in a binomial experiemnt the probability of success is 0.16. what is the probability of two successes in seven trials

Answer 1

0.2248307402

Explanation:

Let 'success', p = 0.16,

and 'failure', q = 1 - 0.16 = 0.84

and the number of trials, n = 7

r = 2

`P(X = r) = \binom{n}{r} {p}^(r) {q}^(n - r) \\ P(X = 2) = \binom{7}{2} {(0.16)}^(2) {0.84}^(5 - 2) \\ = 0.2248307402`