Question

How can I solve that problem

Answer 1

What do we know so far:

• 
  `2(2)/(3)laps` in
  `(4)/(15)hour` ⇒
  `(8)/(3)laps` in
  `(4)/(15)hour`

*we converted the number of laps into improper fractions

`2(2)/(3) = (8)/(3)`

We want to know the number of laps in an hour

⇒ so we must find the rate which ⇒ lap/hour

`lap/hour =(8/3laps)/(4/15hours) =(8)/(3)*(15)/(4) =(8)/(4) *(15)/(3) =2*5=10laps/hour`

So William can run ⇒ 10 laps in one hour

Hope that helps!