Answer:
Explanation:
Let's start by figuring out what the new balance is each time the balance changes, and the number of days with that balance. Then we can take the mean of those balances.
Hint #22 / 4
Day of June Transaction amount (in dollars) New balance Days with that balance
111 122312231223 122312231223 10-1=910−1=910, minus, 1, equals, 9
101010 615615615 1223+615=18381223+615=18381223, plus, 615, equals, 1838 15-10=515−10=515, minus, 10, equals, 5
151515 -63−63minus, 63 1838+(-63)=17751838+(−63)=17751838, plus, left parenthesis, minus, 63, right parenthesis, equals, 1775 22-15=722−15=722, minus, 15, equals, 7
222222 -120−120minus, 120 1775+(-120)=16551775+(−120)=16551775, plus, left parenthesis, minus, 120, right parenthesis, equals, 1655 31-22=931−22=931, minus, 22, equals, 9
[Why subtract from 31?]
Hint #33 / 4
To find the mean, we first sum all of the daily balances. Then we divide by 303030, since there are 303030 days in June.
\begin{aligned}&\phantom{=}\dfrac{1223 \times 9 + 1838 \times 5 + 1775 \times 7 + 1655 \times 9}{30} \\\\ &=\dfrac{11{,}007 + 9190 + 12{,}425 + 14{,}895}{30} \\\\ &=\dfrac{47{,}517}{30} \\\\ &=1583.90 \end{aligned}
=
30
1223×9+1838×5+1775×7+1655×9
=
30
11,007+9190+12,425+14,895
=
30
47,517
=1583.90
Hint #44 / 4
The average daily balance of Elliott's account for the month of June is 1583.901583.901583, point, 90 dollars.