Question

N2 +3H2 → 2NH3 What volume of ammonia at STP is produced if 30.0 g of nitrogen gas is reacted with an excess of hydrogen gas?

Answer 1

V= 48L

Step-by-step explanation:

Moles of N2 = m/M = 30/28= 1.07moles

From the equation of reaction

N2 +3H2 → 2NH3

1mole of N2 produces 2mole of NH3

Hence

1.07moles will produce 1.07×2= 2.14 moles

At STP, 1mole occupy 22.4L

Hence volume of N2 produced = 2.14×22.4= 48 L