Question

60 g of HCL will make how many L of 2.5M HCL? (Molar Mass of HCL = 36.5g/mol)

Answer 1

0.66 L

Step-by-step explanation:

The molarity of a solution is given by:

`M=(n)/(V)` (1)

where

M is the molarity of the solution

n is the number of moles of the solute

V is the volume of the solution

In this problem we have:

`m=60 g` is the mass of the solute (HCl)

`M=2.5` is the molarity of the solution

We also know that the molar mass of HCl is

`M_m=36.5 g/mol`

So, we can find the number of moles of HCl:

`n=(m)/(M_m)=(60)/(36.5)=1.64 mol`

And so using eq(1), we find the volume of the solution:

`V=(n)/(M)=(1.64)/(2.5)=0.66 L`