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Find the sum of 997 + 992 + 987 +...+ 257 +252

User ULazdins
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Answer:

93,675

Explanation:

We see that the given sequence is an arithmetic sequence with first term 997, common difference -5, and last term 252.

The number of terms in the sequence (n) can be found from the formula for the n-th term:

an = a1 +d(n -1)

(an -an)/d +1 = n

(252 -997)/(-5) +1 = n = 150

The sum of these terms is the average of the first and last terms, multiplied by the number of terms:

S150 = (997 +252)/2·150 = 93,675

The sequence sum is 93,675.

User Coherent
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