Question

Solid urea, CN2OH4, (MM=60.06 g) and liquid water are produced by heating ammonia

(MM=17.03 g) gas and carbon dioxide (MM=44.01 g) gas according to the equation
below. This reaction is known to proceed with a percent yield of 85.5%. What is the
theoretical yield if 13.74 g of urea is actually collected?

2NH3(g) + CO2 (g)→CN2OH4(s) + H2O(1)
​

Answer 1

16.1 g

Step-by-step explanation:

Percent yield = (actual / theoretical) x 100

85.5 = (13.74 / theoretical) x 100

0.855 = (13.74 / theoretical)

0.855 (theoretical) = 13.74

theoretical = 13.74 / 0.855

Theoretical = 16.070 = 16.1 g (3 sig figs)